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operator+,-,*,/,%(std::chrono::duration)

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< cpp‎ | chrono‎ | duration

 
 
 
 
std::chrono::duration
Les fonctions membres
Original:
Member functions
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duration::duration
duration::operator=
duration::count
duration::zero
duration::min
duration::max
duration::operator+
duration::operator-
duration::operator++
duration::operator--
duration::operator+=
duration::operator-=
duration::operator*=
duration::operator/=
duration::operator%=
Tiers fonctions
Original:
Non-member functions
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common_type
operator+
operator-
operator*
operator/
operator%
operator==
operator!=
operator<
operator<=
operator>
operator>=
duration_cast
Classes d'aide
Original:
Helper classes
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treat_as_floating_point
duration_values
 
template< class Rep1, class Period1, class Rep2, class Period2 >

typename std::common_type<duration<Rep1,Period1>, duration<Rep2,Period2>>::type
    constexpr operator+( const duration<Rep1,Period1>& lhs,

                         const duration<Rep2,Period2>& rhs );
(1)
template< class Rep1, class Period1, class Rep2, class Period2 >

typename std::common_type<duration<Rep1,Period1>, duration<Rep2,Period2>>::type
    constexpr operator-( const duration<Rep1,Period1>& lhs,

                         const duration<Rep2,Period2>& rhs );
(2)
template< class Rep1, class Period, class Rep2 >

duration<typename std::common_type<Rep1,Rep2>::type, Period>
    constexpr operator*( const duration<Rep1,Period>& d,

                         const Rep2& s );
(3)
template< class Rep1, class Rep2, class Period >

duration<typename std::common_type<Rep1,Rep2>::type, Period>
    constexpr operator*( const Rep1& s,

                         const duration<Rep2,Period>& d );
(4)
template< class Rep1, class Period, class Rep2 >

duration<typename common_type<Rep1,Rep2>::type, Period>
    constexpr operator/( const duration<Rep1,Period>& d,

                         const Rep2& s );
(5)
template< class Rep1, class Period1, class Rep2, class Period2 >

typename std::common_type<Rep1,Rep2>::type
    constexpr operator/( const duration<Rep1,Period1>& lhs,

                         const duration<Rep2,Period2>& rhs );
(6)
template< class Rep1, class Period, class Rep2 >

duration<typename common_type<Rep1,Rep2>::type, Period>
    constexpr operator%( const duration<Rep1, Period>& d,

                         const Rep2& s );
(7)
template< class Rep1, class Period1, class Rep2, class Period2 >

typename common_type<duration<Rep1,Period1>, duration<Rep2,Period2>>::type
constexpr operator%( const duration<Rep1,Period1>& lhs,

                     const duration<Rep2,Period2>& rhs );
(8)
Effectue des opérations arithmétiques de base entre les deux durées ou entre une durée et un nombre de cycles .
Original:
Performs basic arithmetic operations between two durations or between a duration and a tick count.
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1)
Convertit les deux durées de leur type commun et crée une durée de comptage dont la graduation est la somme des chiffres de graduation après conversion .
Original:
Converts the two durations to their common type and creates a duration whose tick count is the sum of the tick counts after conversion.
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2)
Convertit les deux durées de leur type commun et crée une durée dont tique total est le nombre de tiques rhs soustraits du nombre de tiques lhs après conversion .
Original:
Converts the two durations to their common type and creates a duration whose tick count is the rhs number of ticks subtracted from the lhs number of ticks after conversion.
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3-4)
Convertit le d durée de celui dont rep est le type commun entre Rep1 et Rep2, et multiplie le nombre de tiques après conversion par s .
Original:
Converts the duration d to one whose rep is the common type between Rep1 and Rep2, and multiples the number of ticks after conversion by s.
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5)
Convertit le d durée de celui dont rep est le type commun entre Rep1 et Rep2, et divise le nombre de tiques après conversion par s
Original:
Converts the duration d to one whose rep is the common type between Rep1 and Rep2, and divides the number of ticks after conversion by s
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6)
Convertit les deux durées de leur type commun et divise le nombre de cycles de lhs après conversion par le nombre de cycles de rhs après conversion. Notez que la valeur de retour de cet opérateur n'est pas une durée .
Original:
Converts the two durations to their common type and divides the tick count of lhs after conversion by the tick count of rhs after conversion. Note that the return value of this operator is not a duration.
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7)
Convertit le d durée de celui dont rep est le type commun entre Rep1 et Rep2, et crée une durée dont tique total est le reste de la division du comte tique, après la conversion, par s .
Original:
Converts the duration d to one whose rep is the common type between Rep1 and Rep2, and creates a duration whose tick count is the remainder of the division of the tick count, after conversion, by s.
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8)
Convertit les deux durées de leur type commun et crée une durée de comptage dont la graduation est le reste des chiffres après la conversion de tiques .
Original:
Converts the two durations to their common type and creates a duration whose tick count is the remainder of the tick counts after conversion.
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[modifier] Paramètres

lhs -
durée sur le côté gauche de l'opérateur
Original:
duration on the left-hand side of the operator
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rhs -
durée sur la partie droite de l'opérateur
Original:
duration on the right-hand side of the operator
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d -
l'argument de durée mixte arguments opérateurs
Original:
the duration argument for mixed-argument operators
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s -
cochez compter argument en faveur de l'argument des opérateurs mixtes
Original:
tick count argument for mixed-argument operators
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[modifier] Retourne la valeur

En supposant que CD est le type de retour de la fonction et CR<A, B> = std::common_type<A, B>::type, alors:
Original:
Assuming that CD is the function return type and CR<A, B> = std::common_type<A, B>::type, then:
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1) CD(CD(lhs).count() + CD(rhs).count())
2) CD(CD(lhs).count() - CD(rhs).count())
3-4) CD(CD(d).count() * s)
5) CD(CD(d).count() / s).
6)
CD(lhs).count() / CD(rhs).count() (le type de retour de cet opérateur n'est pas une durée)
Original:
CD(lhs).count() / CD(rhs).count() (the return type of this operator is not a duration)
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7) CD(CD(d).count() % s)
8) CD(CD(lhs).count() % CD(rhs).count())


[modifier] Exemple

#include <chrono>
#include <iostream>
int main()
{
    // simple arithmetic
    std::chrono::seconds s = std::chrono::hours(1) 
                             + 2*std::chrono::minutes(10)
                             + std::chrono::seconds(70)/10;
 
    std::cout << "1 hour + 2*10 min + 70/10 sec = " << s.count() << " seconds\n";
 
    // difference between dividing a duration by a number
    // and dividing a duration by another duration
    std::cout << "Dividing that by 2 minutes gives "
              << s / std::chrono::minutes(2) << '\n';
    std::cout << "Dividing that by 2 gives "
              << (s / 2).count() << " sconds\n";
 
   // the remainder operator is useful in determining where in a time
   // frame is this particular duration, e.g. to break it down into hours,
   // minutes, and seconds:
   std::cout << s.count() << " seconds is "
             << std::chrono::duration_cast<std::chrono::hours>(
                    s
                ).count() << " hours, "
             << std::chrono::duration_cast<std::chrono::minutes>(
                    s % std::chrono::hours(1)
                ).count() << " minutes, "
             << std::chrono::duration_cast<std::chrono::seconds>(
                    s % std::chrono::minutes(1)
                ).count() << " seconds\n";
}

Résultat :

1 hour + 2*10 min + 70/10 sec = 4807 seconds
Dividing that by 2 minutes gives 40
Dividing that by 2 gives 2403 sconds
4807 seconds is 1 hours, 20 minutes, 7 seconds